2m^2=19m-35

Solution for 2m^2=19m-35 equation:

2m^2=19m-35

We move all terms to the left:

2m^2-(19m-35)=0

We get rid of parentheses

2m^2-19m+35=0

a = 2; b = -19; c = +35;
Δ = b2-4ac
Δ = -192-4·2·35
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-9}{2*2}=\frac{10}{4}
=2+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+9}{2*2}=\frac{28}{4}
=7
$